Tuesday 2-22 Erick

To Begin class today we went over the lab test from Friday and went over many different ways to solve the problem. To Refresh on Friday we were given salt and asked to create a solution with a .15 molarity. One of the ways that was brought up was to use a sample volume and calculate the number of mols. Here's a different way to solve the problem.

.15M= Mol’s Liters 1.5 g NaCl 1mol

58.44 g NaCl 1.5/58.44

.15M= .o2567mol/ x

.171L

171ML

After we went over the different ways to solve the lab quiz we were given a sheet to complete on chemthink. To get to the lab go to chemthink click labs chemical reations labs and then click Precipitate lab.

After we briefly went over the lab we took notes on the rules of solubility.

Compounds always Soluble in water	Unless they have this
Ammonium NH4
Potassium K
Sodium Na
Nitrate NO3
Chlorine CL	Ag Hg Pb
Acetate C2 H3 O2	Fe Al Hg2
Sulfate	Ca Ba Pb Sr Hg2

Compounds always insoluble	Unless they have this
Oxide O2	K Na NH4 LI
Carbonate Co3	K Na LI NH4
Hydroxide OH	K Na Ba LI
Phosphate PO4	K Na NH4
Silicate SiO3	K Na
Sulfide S2	K Na NH4
Sulfite SO3	K Na NH4

The homework for the night was to Complete the lab on chemthink and to continue practicing solubility reatcions.